simple "Round" function

[Todd Reed]

I was struggling with a simple decimal rounding issue and found this code snippet.



function round (n,shift)
shift = 10^shift
return math.floor ((n*shift)+0.5)/shift
end


simple call it with your value...


a = round (1234.567, 0) -- gives "1235"
a = round (1234.567, 1) -- gives "1234.6"
a = round (1234.567, -2) -- gives "1200"


Hope this helps others... :D

[Rob H]

Very nice. Although I'd probably change it as follows so that you can omit the second parameter :-


function round (n,shift)
shift = 10^(shift or 0)
return math.floor ((n*shift)+0.5)/shift
end


Ron: Do you think this should be added to addtions.lua so that it's available in the math library?

[Promixis]

there is a math.round function already :)

[birty]

the above function allows you to specify a precision though and with rob's modification is compatible with the current function

[Todd Reed]

I did not see it in the manual.... :x

[birty]

thats because its not in there. Its always worth checking the variable inspector though

[Ron]

I've modified in the internal round to work like the round here, which is compatible with the old implementation of round.